Categories
City size

How big is Venice, Florida?

Size is not all that matters. But still, we would love to know how big Venice in Florida is. Here is the answer:

Venice, Florida covers an area of 43.54 square kilometers (16.81 square miles).

With 17,764 people living in Venice that comes to a population density of 407.99 inhabitants per square kilometer (1056.75 / sq mi)

As a reference: The 8,398,748 people living in New York City are crammed onto 1214 sq km (468.73 sq mi), which results into a population density of 6918 inhabitants per square kilometer (17918 / sq mi).

The population density of Venice in Florida is 43.54 square kilometers (16.81 square miles)

Venice is a city in Sarasota County, Florida, United States. The city includes what locals call “Venice Island”, a portion of the mainland that is accessed via bridges over the artificially created Intracoastal Waterway. The city is located south of Nokomis and north of Englewood. As of the 2010 census, the city had a population of 20,746. It is noted for its large snowbird population and was voted as a top 10 Happiest Seaside Towns by Coastal Living.Venice is part of the North Port–Sarasota–Bradenton metropolitan statistical area.

Cities with a similar size as Venice

If you want to check which cities have a similar size as Venice, Florida, here you go:

Cities with a similar population density as Venice

Other cities that have a similar population density as Venice, Florida are:

Cities with a similar population size as Venice

Here a list of cities that have a similar number of inhabitants like Venice, Florida: