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Population Density

What is the population density of Hobart, Indiana?

Have you ever wondered how many people are crammed into Hobart in Indiana? Here is the answer:

Hobart, Indiana has a population density of 421.82 inhabitants per square kilometer (1092.44 / sq mi)

That means the whole population of 29,059 people are living within an area of 68.89 sq km (26.6 sq mi).

As a reference: New York City has a population density of 6918 inhabitants per square kilometer (17918 / sq mi), thanks to it’s population of 8,398,748 inhabitants within an area of 1214 sq km (468.73 sq mi).

The population density of Hobart in Indiana is 421.82 people per square kilometer (1092.44 / sq mi)

Hobart is a city in Lake County, Indiana, United States. The population was 29,059 at the 2010 census. Although it has been historically primarily residential, recent annexation has added a significant retail corridor to the city.

Cities with a similar population density as Hobart

Other cities that have a similar population density as Hobart, Indiana are:

Cities with a similar population size as Hobart

Here a list of cities that have a similar number of inhabitants like Hobart, Indiana:

Cities with a similar size as Hobart

If you want to check which cities have a similar size as Hobart, Indiana, here you go: