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Population Density

What is the population density of Lompoc, California?

Have you ever wondered how many people are crammed into Lompoc in California? Here is the answer:

Lompoc, California has a population density of 1403.7 inhabitants per square kilometer (3636.16 / sq mi)

That means the whole population of 42,434 people are living within an area of 30.23 sq km (11.67 sq mi).

As a reference: New York City has a population density of 6918 inhabitants per square kilometer (17918 / sq mi), thanks to it’s population of 8,398,748 inhabitants within an area of 1214 sq km (468.73 sq mi).

The population density of Lompoc in California is 1403.7 people per square kilometer (3636.16 / sq mi)

Lompoc (, LOM-poke) (Purisimeño: Lompo’, “Stagnant Water”) is a city in Santa Barbara County, California. The city was incorporated on August 13, 1888. The population was 42,434 at the 2010 census, up from 41,103 at the 2000 census.Before European settlers arrived, the area around Lompoc was inhabited by the Chumash people. The name of the city is derived from a Purisimeño term, “Lum Poc”, which means “stagnant waters” or “lagoon”. In 1837, the Mexican government sold the area as the Rancho Lompoc land grant. After the United States gained control of California in the Mexican–American War (1846–48), the valley was acquired by Thomas Dibblee, Albert Dibblee and William Welles Hollister. Hollister sold his share to the Lompoc Valley Land Company, and it was on that portion of the land that the present-day Lompoc was established as a temperance colony. Lompoc was originally intended to be named New Vineland, after the temperance colony in New Jersey. It then became a military town with the completion of nearby Camp Cooke (now Vandenberg Air Force Base). The city is known as the flower seed capital of the world.

Cities with a similar population density as Lompoc

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Cities with a similar population size as Lompoc

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Cities with a similar size as Lompoc

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