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City size

How big is American Fork, Utah?

Size is not all that matters. But still, we would love to know how big American Fork in Utah is. Here is the answer:

American Fork, Utah covers an area of 26.06 square kilometers (10.06 square miles).

With 27,147 people living in American Fork that comes to a population density of 1041.71 inhabitants per square kilometer (2698.51 / sq mi)

As a reference: The 8,398,748 people living in New York City are crammed onto 1214 sq km (468.73 sq mi), which results into a population density of 6918 inhabitants per square kilometer (17918 / sq mi).

The population density of American Fork in Utah is 26.06 square kilometers (10.06 square miles)

American Fork is a city in north-central Utah County, Utah, United States, at the foot of Mount Timpanogos in the Wasatch Range, north of Utah Lake. It is part of the Provo–Orem Metropolitan Statistical Area. The population was 32,519 in 2018, representing a nearly 20% growth since the 2000 census. The city has grown rapidly since the 1970s.

Cities with a similar size as American Fork

If you want to check which cities have a similar size as American Fork, Utah, here you go:

Cities with a similar population density as American Fork

Other cities that have a similar population density as American Fork, Utah are:

Cities with a similar population size as American Fork

Here a list of cities that have a similar number of inhabitants like American Fork, Utah: