What is the population of Seymour in Indiana?

If you ever wondered how many inhabitants Seymour in Indiana has, here is the answer:

Seymour, Indiana has a population of 17,503 residents.

With an area of 30.99 sq km (11.97 sq mi), that comes down to a population density of 564.8 inhabitants per square kilometer (1462.24 / sq mi).

As a reference: New York City has a population of 8,398,748 inhabitants and a population density of 6918 inhabitants per square kilometer (17918 / sq mi).

The population of Seymour in Indiana is 17503

Seymour is a city in Jackson County, Indiana, United States. The population was 17,503 at the 2010 census. Indiana is referred to as the “Crossroads of America.” Seymour holds particular significance due to the north/south and east/west railroads intersecting downtown.The north/south line (the Jeffersonville, Madison and Indianapolis Railroad) was built in the 1840s and connected Indianapolis to the Ohio River at Jeffersonville. In 1852, Capt. Meedy Shields persuaded John Seymour into building the east/west railroad (the Ohio and Mississippi Railroad) through his land. In return, Shields named the area Seymour.Aisin USA and Rose Acre Farms have their headquarters in Seymour, and Cummins has a plant in Seymour. The city is also the home of the largest high school gymnasium in the world.

Cities with a similar population size as Seymour

Here a list of cities that have a similar number of inhabitants like Seymour, Indiana:

Cities with a similar size as Seymour

If you want to check which cities have a similar size as Seymour, Indiana, here you go:

Cities with a similar population density as Seymour

Other cities that have a similar population density as Seymour, Indiana are:

Cities from the same state: Indiana

Let’s see what other cities Indiana has to offer: